Physics, asked by tomba7968, 1 year ago

The wavelength \lambda_{e} of an electron and \lambda_{p} of a photon are of same energy E are related by(a) \lambda_{p}\propto\lambda_{e}(b) \lambda_{p}\propto\sqrt{\lambda_{e}}(c) \lambda_{p}\propto\frac{1}{\sqrt{\lambda_{e}}}(d) \lambda_{p}\propto\lambda_{e}^{2}

Answers

Answered by dynamogirl
1

{\huge{\boxed{ANSWER}}}

Option B is your answer

Thanks!!!

Answered by ItzMiracle
0

Explanation:

option B

hope you find it helpful

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