Question

the wavelength to show photoelectric effect is 200 nm calculate the wavelength of radiation required to produce photo electrons with half of the k E of the photoelectrons emitted by the radiation of wavelength 120 nm.​

Answer 1

Answer:

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Answer 2

Given that,

Given that,The maximum wave length λ

Given that,The maximum wave length λ 0

Given that,The maximum wave length λ 0

Given that,The maximum wave length λ 0 =200nm

Given that,The maximum wave length λ 0 =200nmRadiation of wave length λ=100nm

Given that,The maximum wave length λ 0 =200nmRadiation of wave length λ=100nmWe know that, the maximum K.E is

Given that,The maximum wave length λ 0 =200nmRadiation of wave length λ=100nmWe know that, the maximum K.E is K.E=12400[

Given that,The maximum wave length λ 0 =200nmRadiation of wave length λ=100nmWe know that, the maximum K.E is K.E=12400[ λ

Given that,The maximum wave length λ 0 =200nmRadiation of wave length λ=100nmWe know that, the maximum K.E is K.E=12400[ λ1

Given that,The maximum wave length λ 0 =200nmRadiation of wave length λ=100nmWe know that, the maximum K.E is K.E=12400[ λ1

Given that,The maximum wave length λ 0 =200nmRadiation of wave length λ=100nmWe know that, the maximum K.E is K.E=12400[ λ1 −

Given that,The maximum wave length λ 0 =200nmRadiation of wave length λ=100nmWe know that, the maximum K.E is K.E=12400[ λ1 − λ

Given that,The maximum wave length λ 0 =200nmRadiation of wave length λ=100nmWe know that, the maximum K.E is K.E=12400[ λ1 − λ 0

Given that,The maximum wave length λ 0 =200nmRadiation of wave length λ=100nmWe know that, the maximum K.E is K.E=12400[ λ1 − λ 0

Given that,The maximum wave length λ 0 =200nmRadiation of wave length λ=100nmWe know that, the maximum K.E is K.E=12400[ λ1 − λ 0

Given that,The maximum wave length λ 0 =200nmRadiation of wave length λ=100nmWe know that, the maximum K.E is K.E=12400[ λ1 − λ 0 1

Given that,The maximum wave length λ 0 =200nmRadiation of wave length λ=100nmWe know that, the maximum K.E is K.E=12400[ λ1 − λ 0 1

Given that,The maximum wave length λ 0 =200nmRadiation of wave length λ=100nmWe know that, the maximum K.E is K.E=12400[ λ1 − λ 0 1 ]

Given that,The maximum wave length λ 0 =200nmRadiation of wave length λ=100nmWe know that, the maximum K.E is K.E=12400[ λ1 − λ 0 1 ] K.E=12400[

Given that,The maximum wave length λ 0 =200nmRadiation of wave length λ=100nmWe know that, the maximum K.E is K.E=12400[ λ1 − λ 0 1 ] K.E=12400[ 1000

Given that,The maximum wave length λ 0 =200nmRadiation of wave length λ=100nmWe know that, the maximum K.E is K.E=12400[ λ1 − λ 0 1 ] K.E=12400[ 10001

Given that,The maximum wave length λ 0 =200nmRadiation of wave length λ=100nmWe know that, the maximum K.E is K.E=12400[ λ1 − λ 0 1 ] K.E=12400[ 10001

Given that,The maximum wave length λ 0 =200nmRadiation of wave length λ=100nmWe know that, the maximum K.E is K.E=12400[ λ1 − λ 0 1 ] K.E=12400[ 10001 −

Given that,The maximum wave length λ 0 =200nmRadiation of wave length λ=100nmWe know that, the maximum K.E is K.E=12400[ λ1 − λ 0 1 ] K.E=12400[ 10001 − 2000

Given that,The maximum wave length λ 0 =200nmRadiation of wave length λ=100nmWe know that, the maximum K.E is K.E=12400[ λ1 − λ 0 1 ] K.E=12400[ 10001 − 20001

Given that,The maximum wave length λ 0 =200nmRadiation of wave length λ=100nmWe know that, the maximum K.E is K.E=12400[ λ1 − λ 0 1 ] K.E=12400[ 10001 − 20001

Given that,The maximum wave length λ 0 =200nmRadiation of wave length λ=100nmWe know that, the maximum K.E is K.E=12400[ λ1 − λ 0 1 ] K.E=12400[ 10001 − 20001 ]

Given that,The maximum wave length λ 0 =200nmRadiation of wave length λ=100nmWe know that, the maximum K.E is K.E=12400[ λ1 − λ 0 1 ] K.E=12400[ 10001 − 20001 ] K.E=12400×

Given that,The maximum wave length λ 0 =200nmRadiation of wave length λ=100nmWe know that, the maximum K.E is K.E=12400[ λ1 − λ 0 1 ] K.E=12400[ 10001 − 20001 ] K.E=12400× 2000

Given that,The maximum wave length λ 0 =200nmRadiation of wave length λ=100nmWe know that, the maximum K.E is K.E=12400[ λ1 − λ 0 1 ] K.E=12400[ 10001 − 20001 ] K.E=12400× 20001

Given that,The maximum wave length λ 0 =200nmRadiation of wave length λ=100nmWe know that, the maximum K.E is K.E=12400[ λ1 − λ 0 1 ] K.E=12400[ 10001 − 20001 ] K.E=12400× 20001

Given that,The maximum wave length λ 0 =200nmRadiation of wave length λ=100nmWe know that, the maximum K.E is K.E=12400[ λ1 − λ 0 1 ] K.E=12400[ 10001 − 20001 ] K.E=12400× 20001

Given that,The maximum wave length λ 0 =200nmRadiation of wave length λ=100nmWe know that, the maximum K.E is K.E=12400[ λ1 − λ 0 1 ] K.E=12400[ 10001 − 20001 ] K.E=12400× 20001 K.E=6.2eV

Given that,The maximum wave length λ 0 =200nmRadiation of wave length λ=100nmWe know that, the maximum K.E is K.E=12400[ λ1 − λ 0 1 ] K.E=12400[ 10001 − 20001 ] K.E=12400× 20001 K.E=6.2eVHence, the kinetic energy is 6.2 eV