the wavelengthof radiation required to remove the electron of hydrogen atom (Ionisation energy 21.7into 10^-7)erg from n=2orbit to n=infinity
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Answer:
3.67 * 10⁻⁵ cm
Explanation:
To calculate the energy required to remove electron from atom, n = ∞ is to be taken.
Energy of an electron in nth orbit of hydrogen is given by
E = 21.7 * 10⁻¹² * 1/n² ergs
∴ ∆E = 21.7 * 10⁻¹² (1/2² – 1/∞²)
= - 21.7 * 10⁻¹² (1/4 – 0) = 21.7 * 10⁻¹² * 1/4
= - 5.42 * 10⁻¹² ergs
∴ ∆E = hc/λ (∵ v = c/λ)
Or λ = hc/∆E
Substituting the values, λ = 6.627 *10⁻²⁷ *3 *1010/5.42 * 10⁻¹²
= 3.67 * 10⁻⁵ cm
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