Question

The wavenumber for the shortest wavelength transition in the Balmer series of atomic hydrogen is​

Answer 1

Answer:

1

It is your answer buddy!

Answer 2

$v = r( \frac{1}{ {n1}^{2} } - \frac{1}{ {n2}^{2} } ) {z}^{2}$

here N1 =2

and N2 is infinity .

hope it helps u