Biology, asked by faiyajansari6062, 1 year ago

The wax is coated on the inner wall of a capillary tube is then dipped in water then compared to an axe to capillary

Answers

Answered by aqsaahmed19945
2

When angle of contact increases, h decreases .

Edge of contact \[\cos \theta =\frac{{{ T }_{SA}}-{{T}_{ SL }}}{{{T}_{LA}}}\] when water is on a waxy or sleek surface \[{{T}_{SA}}<{{T}_{SL}}\cos \theta \] is negative i.e.,\[{{90}^{o}}<\theta <{{180}^{o}}\] i.e., point of contact \[\theta \]increases And for \[\theta >{{90}^{o}}\] fluid dimension in slim cylinder fall. i.e., h diminishes .

Answered by aqibkincsem
4

When the wax is quoted on the inner walls of a capillary tube and then dipped in water, and when we compare this with an unwaxed tube the angle of contact and the height changes accordingly.

In the changes that are observed the angle of contact increases and the height of the capillary tube decreases when in water.

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