The weekly wages of 1000 workmen are normally distributed around a mean of#70 and a standard deviation of #5 estimate the number of workers whose weekly wages will be
More than#75
Less than#63
Answers
Given : The weekly wages of 1000 workmen are normally distributed around a mean of 70 and a standard deviation of 5
To Find : estimate the number of workers whose weekly wages will be
More than 75
Less than 63
Solution:
Mean = 70
SD = 5
Z score = ( Value - Mean ) / SD
More than 75
=> z score = ( 75 - 70)/5 = 1
=> 84.13 % less than 75 Hence 15.87 % more than 75
=> 1000 * 15.87 /100 = 158.7 = 159
159 workers whose weekly wages will be More than 75
Less than 63
=> z score = ( 63 - 70)/5 = -1.4
= 8.08 % less than 63
=> 1000 * 8.08 /100 = 80.8 = 81
81 workers whose weekly wages will be Less than 63
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