Question

the weight if a bix is 120N .When immeresed completely in a water the weight becomes 80N.what is a relative density of the material of the block?​

Answer 1

Given ;

original weight

• O = 120N

Weight found while immersed

• I = 80N

Thus change in weight

• = 120 - 80
• = 40N

Thus the specific Gravity or the relative density

=

$\frac {Change \: in \: weight}{Original \: weight}$

$\frac{40}{120} = > \frac{4}{12 } = > \frac{1}{3}$

Thus the relative density=

$\frac{1}{3}$

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