Question

The weight in grams of O2 formed at Pt anode
during the electrolys of aq. K2SO4
solution
during the passage of one coulomb of electricity is
1)16/96800
2)8/96500
3)32/96500
4)64/96500
​

Answer 1

Answer:

answer is option 2

Explanation:

as OH-ion is more dominant over so4-2ions in aqueous solution of k2so4 solution

we said, according to faradays laws

96,500c(1 farad)---------8gm of O2is liberated at anode

1 c-----------------?gm of O2

then after solving we get 8/96500 as answer

hope you understand this