Chemistry, asked by 8308564179, 9 months ago

The weight of 0.112L of N2 gas at STP is ​option are:a)2.8g,b)0.14g,c)0.036g,d)3.8g

Answers

Answered by anuragmitra12
2

Answer:

(b) 0.14g

Explanation:

According to Avogadro's Law, equal volumes of all gases under same conditions of temperature and pressure contains same number of molecules. We know at STP 1 mole of any gas occupies a volume of 22.4L. So 1 mole of N2(which weighs 28g) will occupy 22.4L volume at STP. So by unitary method of 22.4L N2 weighs 28g, then 0.112 L of N2 will weigh 0.14g.

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