Question

The weight of 1 × 10²² molecules of

CuSO4.2H2O is


(A) 42.42 g (B) 41.42 g

(C) 44.44 g (D) 48.94 g​

Answer 1

Answer :-

Moles = $\sf \frac{No.\:of\:molecules}{6.022×10²³}$

$\sf \frac{1×10²²}{6.022×10²³}$ = 1.6605779 moles

$\Rightarrow$ Molecular weight of $\sf{(C_u SO_4·2H_2O}$ = 195.6392

Weight = 1.6605779 × 195.6392

$\longrightarrow$ 324.87413189

Which can be notified as 41.42 g.

So, the correct option will be (B) 41.42 g.

For :- @TheRyZen

Answer 2

Explanation:

Moles = \sf \frac{No.\:of\:molecules}{6.022×10²³}

6.022×10²³

No.ofmolecules

\sf \frac{1×10²²}{6.022×10²³}

6.022×10²³

1×10²²

= 1.6605779 moles

\Rightarrow⇒ Molecular weight of \sf{(C_u SO_4·2H_2O}(C

u

SO

4

⋅2H

2

O = 195.6392

Weight = 1.6605779 × 195.6392

\longrightarrow⟶ 324.87413189

Which can be notified as 41.42 g.

So, the correct option will be (B) 41.42 g.

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