Question

the weight of 1mole of agas of density 0.1784gm/lit at ntp

Answer 1

vol=1/22.4
so , as we knw that
density = wt./volume
wt.=d×v
=0.1784×1/22.4
=0.0784g

Answer 2

Answer: The weight of the gas is 0.004 kg.

From the given,

1 mole of gas of a gas density 0.1784 g/L

At NTP, volume of gas = 22.4 L

$Density\quad =\quad \frac { Mass }{ Volume }$

Volume is the “space” occupied by an “object”.

Rearrange the formula is as follows.

$Mass\quad =\quad Density\quad \times \quad Volume$

Mass is equal to density times volume.

$=\quad 0.1784\quad g/L\quad \times \quad 22.4\quad L$

$Mass\quad =\quad 4\quad g\quad =\quad 0.004\quad kg$