Question

the weight of 350 ml of a distace gas at 0 degree and 2 atm is 1 gm find the weight of one atom

Answer 1

Answer:

use formula PV=nRT

P=2atm

V=350ml.=0.35L

R=0.0821L atm K-1 mol-1

T=0ºC=273K

putting values in given formula we get:n=PV/RT

=2atm K-1mol-1×273K

=0.0312 mol