the weight of 350 ml of a distace gas at 0 degree and 2 atm is 1 gm find the weight of one atom
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Answer:
use formula PV=nRT
P=2atm
V=350ml.=0.35L
R=0.0821L atm K-1 mol-1
T=0ºC=273K
putting values in given formula we get:n=PV/RT
=2atm K-1mol-1×273K
=0.0312 mol
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