Question

The weight of 350ml of a diatomic gas is 1 gram at 0°C and 2atm pressure. The weight of 1 atom in grams

Answer 1

Use the formula PV = nRT
​P = 2 atm
V = 350 ml. = 0.35 L
R = 0.0821 L atm K-1 mol-1
T = 0º​ C = 273 K
Putting the values in given formula we get :
n = PV/RT
= ​2 atm x 0.35 L/ 0.0821 L atm K-1 mol-1​ x 273 K
= 0.0312 mol
Now weight of 0.0312 mol of gas is 1 gram
therefore weight of 1 mol of gas would be 1/0.0312 = 32 g mol-1
Since the gas is diatomic therefore weight of 1 mole atom = 16 g mol-1
Weight of 1 atom of gas = 16 g mol-1/ 6.022 x 1023 atom mol-1
= 2.65 x 10-23 g /atom

Answer 2

Answer:

Use the formula PV = nRT​P = 2 atm V = 350 ml. = 0.35 L R = 0.0821 L atm K-1 mol-1 T = 0º​ C = 273 K Putting the values in given formula we get : n = PV/RT = ​2 atm x 0.35 L/ 0.0821 L atm K-1 mol-1​ x 273 K = 0.0312 mol Now weight of 0.0312 mol of gas is 1 gram therefore weight of 1 mol of gas would be 1/0.0312 = 32 g mol-1 Since the gas is diatomic therefore weight of 1 mole atom = 16 g mol-1 Weight of 1 atom of gas = 16 g mol-1/ 6.022 x 1023 atom mol-1 = 2.65 x 10-23 g /atomRead more on Sarthaks.com - https://www.sarthaks.com/6929/the-weight-of-350-ml-of-diatomic-gas-at-0c-and-2-atm-pressure-is-1-g-what-is-atomic-mass-of-it