The weight of a body in air is 100 N.How much will it weight in water if it displaces 400 cc of water?(g = 9.8 m/s2
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Answer:
Explanation:
Given that,
Weight of body in air =
100
N
Buoyant force = Weight of liquid displaced
Volume of water displaced =
400
c
c
2
Density of water =
1
g
/
c
m
3
In this case,
ρ
=
m
V
m
=
ρ
×
V
m
=
1
×
400
m
=
400
g
We know that,
The weight of water displaced is
W
=
m
×
g
W
=
2
5
×
9.8
W
=
3.92
N
Now, weight of the object in water
W
=
100
−
3.92
W
=
96.08
W
=
96
N
Hence, the weight of object in water is
96
N
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