Question

the weight of a body in water is 100N. the water exerted a buoyancy of 20N. calculate the weight of the body in air???​

Answer 1

Answer:

Explanation:

Given that,

Weight of body in air = 100 N

Buoyant force = Weight of liquid displaced

Volume of water displaced = 400 cc

2

Density of water = 1g/cm3

In this case,

 ρ=

V

m

​

m=ρ×V

m=1×400

m=400g

We know that,

The weight of water displaced is

 W=m×g

W=

5

2

​

×9.8

W=3.92N

Now, weight of the object in water

 W=100−3.92

W=96.08

W=96N

Hence, the weight of object in water is 96 N