Question

the weight of a body on the earth's surface formula

Answer 1

Hey, mate here is your answer✌✌》》

Let the body have the mass M, measured in kilograms (kg).

At the surface of the earth — well, the surface of the earth varies, doesn’t it.

And the force of gravity is inversely proportional to the distance from the center of mass. So, the farther away an object is from the center, the less effect the Earth’s gravity will have on it.

At the summit of Everest the body will weigh less than at the shore of the Dead Sea.

So we need a reference for measuring elevation. The most typical one is commonly referred to as ‘sea level’.

At that level, 1 kg of mass (1 kgm) weighs 1 kg of force (1 kgf). And that works out to 9.8 Newtons (N).

So, whatever M is in kg of mass, the weight at sea level is the same in kg of force, and would be multiplied by 9.8 to get Newtons.

Since you don’t say anything about this ‘body,’ you’ll just have to do the math yourself.

Hope this answer will help you..《《

#Be Brainly#
@1Angel24

Answer 2

We can calculate the ratio of the gravitational constant to the value at the surface of the Earth as the square of (4000/4007) which equals .9965. If the rocket weighs 100 pounds on the surface of the Earth, it weighs 99.65 pounds at 35000 feet; it has lost .35 pounds, a very small amount compared to 100 pounds.

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