The weight of a body which is immersed in water is 800 N. The weight of water
Displaced by the body is 120 N. What is the weight of the body in air ?
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Answer:
Given that,
Weight of body in air = 100 N
Buoyant force = Weight of liquid displaced
Volume of water displaced = 400 cc
2
Density of water = 1g/cm3
In this case,
ρ=
V
m
m=ρ×V
m=1×400
m=400g
We know that,
The weight of water displaced is
W=m×g
W=
5
2
×9.8
W=3.92N
Now, weight of the object in water
W=100−3.92
W=96.08
W=96N
Hence, the weight of object in water is 96N
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