Question

The weight of a gaseous mixture containing 12.044x10” atoms of
He and 3.011x10” molecules of hydrogen is​

Answer 1

Explanation:

weight of He = 12.044×10×4/6.022×10^23=2×4×10^-22

=8×10^-22g

weight of H2= 3.011×10×2/6.022×10^23

=1×20/2×10^23 =1×10^-22

weight of mixture = 9×10^-22g