Question

The weight of a metal bar varies jointly as its Length metres and the square of its diameter. If weight= 140 when diameter= 4 and length= 54. Find diameter in terms of weight and length. [Jamb]

Answer 1

Answer:

Explanation

(Winfty LD^2\W=KLd^2\K=frac{W}{Ld^2}\=frac{140}{54}timesleft(4frac{2}{3}right)^2 \=frac{140}{54}timesleft(frac{14}{3}right)^2\=frac{140times 9}{54times 14times 14}\=frac{5}{42}\∴W=frac{5}{42Ld^2}\42W=5Ld^2\frac{42W}{5L}=d^2\d=sqrt{frac{42W}{5L}})

Step-by-step explanation:

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