Question

The weight of a rider driving a scooter is assumed to be distributed equally on both the tyres. The area of contact of each tyre is 10 cm2. If the pressure inside the tyre is 3 x 105 Pa, find the mass of the rider.​

Answer 1

Answer:

Area of contact of each tyre =10cm

2

Area of contact of two tyres (A)

=2×10cm

2

=20cm

2

=20×10

−4

m

2

(∴1cm

2

=10

−4

m

2

)

Pressure(P)=2bar=2×10

5

Pa(∴1bar=10

5

Pa)

Weight of the person=pressure×area

W=P×A=2×10

5

×20×10

−4

=400N

Weight of the person is 400 N.

Mass of the person (m)

=

g

W

=

10

400

=40kg