the weight of a rider is asumed to be evenly distributed on both tyres the area of contact with eachtype of ground is 10 cm 2 if the presure inside is 3 bars find the mass of rider g= 10 m-2
Answers
Answer:
Contact area of each tyre = 10cm
2
=10
−3
m
2
Net area of contact = 2×10
−3
m
2
Pressure = 3 bar = 3×10
5
P
a
Force = Pressure × Area = 3×10
5
×2×10
−3
N
= 6×10
2
N
Force on two tyres = 600 N
Hence mass of ryder =
2×10
600
=30kg.
Answer ByContact area of each tyre = 10cm
2
=10
−3
m
2
Net area of contact = 2×10
−3
m
2
Pressure = 3 bar = 3×10
5
P
a
Force = Pressure × Area = 3×10
5
×2×10
−3
N
= 6×10
2
N
Force on two tyres = 600 N
Hence mass of ryder =
2×10
600
=30kg.
Answer ByContact area of each tyre = 10cm
2
=10
−3
m
2
Net area of contact = 2×10
−3
m
2
Pressure = 3 bar = 3×10
5
P
a
Force = Pressure × Area = 3×10
5
×2×10
−3
N
= 6×10
2
N
Force on two tyres = 600 N
Hence mass of ryder =
2×10
600
=30kg.