Question

The weight of a stone is 50 kgf. What will be its weight, if it is completely immersed in water?​

Answer 1

Answer:

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Explanation:

Density ρ  = 5000 kg/m3

Weight = 0.5 kg f in air

mass M = 0.5 kg 

Volume V = M / ρ 

           = 0.5 / 5000 = 10−4m3

mass of water displaced = V∗ density of water

  = 10−4∗1000 = 0.1 kg  

Apparent weight = wt in air - wt of water displaced

                           = 0.5 kg f - 0.1 kg f 

                           = 0.4 kg f