Math, asked by devanshs6, 4 months ago

The weight of an alloy of gold and silver in air is 30 gram and in water is 28 gram. Find the weight of gold and silver in the alloy separately assuming that there is a loss of 1/10 and 1/19 of its own weight in silver and gold respectively?​

Answers

Answered by 5346720arnavtyagi
1

Answer:

Let the amount of copper in the ornament be x g, then the volume of the ornament  will be given by the Relation,

V = Volume of copper + volume of gold

Now, Volume of the Copper = Mass/Density = x/8.9

Volume of the Gold = Mass/Density = (36 - x)/19.3

Therefore,

Volume of the Copper = (x/8.9) + (36 - x)/19.3

Now, Using the Principle of Flotation,

loss in weight = 36g - 34g

(x/8.9) + (36-x)/19.3 = 2

x ≈ 2.2 g

Hope it helps .

Answered by mssssverma
0

Answer:

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