Science, asked by maria9, 1 year ago

The weight of an object at the centre of the earth of radius R is
(a) zero
(b) infinite
(c) R times the weight at the surface of the earth
(d) 1/R2 times the weight at surface of the earth

Answers

Answered by ImRitz
92
(a) Zero
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The weight of an object at centre of the earth of radius R is zero.
Answered by kingofself
57

The "weight of an object" at earth centre of 'radius R' is zero.

Answer - (Option A)

Explanation:

  • The weight of an object is the force with that an object is attracted towards the earth centre.
  • The weight (W) of a body is the "product of its mass" (m) and the "acceleration due to gravity".  

                                                     W = mg

  • The "acceleration due to gravity" g at the earth centre is zero.  

                             g^{\prime}=g\left(1-\frac{h}{R}\right)

     When h is the distance from the earth’s surface to the earth’s centre and at the centre of the earth, h = R and g^{\prime}= 0

                        So, w = mg = m\times0 =0

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