the weight of an object in water is equal to its weight in air minus
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Explanation:
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Answer:
Weight of object in water = weight of object in vacuum - buoyant force.
But Archimedes principle states that the buoyant force = weight of fluid displaced by object.
Therefore weight of object in water = weight of object in vacuum - weight of water displaced by it……………equation 1
To get the weight of water displaced (buoyant force), put water in a calibrated cylinder or beaker, measure the volume before immersing the object and then the volume after immersing the object. This would be the change in volume ΔV
From this volume you can get the mass of water displaced since the density of water is 977kg/m^3.
Density = mass/volume, ………..equation 2
Thus mass = density * volume………….equation 3
Mass in this case = 977kg/m^3* ΔV………..equation 4
Whatever you get multiply it by 9.8m/s^2 to covert mass to weight. This would be the weight of fluid displaced or buoyant force. Having measured the weight of the object in a vacuum, apply this value of weight of displaced fluid to equation 1 to get the weight of the object in water.