the weight of an object is 5N. At a certain instant its momentum is 6kgms-1. Due to a force applied in the direction opposite to the direction of motion the velocity is of the object decreased to 4ms-1 during 4s. what is the force exerted on the object?
Answers
Answered by
15
Heya user !!
Here's the answer you are looking for
Please see the attached file for your answer
★★ HOPE THAT HELPS ☺️ ★★
Here's the answer you are looking for
Please see the attached file for your answer
★★ HOPE THAT HELPS ☺️ ★★
Attachments:
Answered by
10
weight = mg
so here weight is given as 5N
so mass =5/g =5/10= 0.5kg
now momentum is given as
6kgms^-1
p=m×v
so, 6=0.5×v
so v=12m/s
now acc to equation of motion v=u+at
so time=4s
v=4m/s
u=12m/s
so a=(4-12)/4
a=-8/4
a=-2m/s^2
-ve tell about the opposite direction.
now force = ma
so F=0.5×-2
F=-1N
in opposite direction
so here weight is given as 5N
so mass =5/g =5/10= 0.5kg
now momentum is given as
6kgms^-1
p=m×v
so, 6=0.5×v
so v=12m/s
now acc to equation of motion v=u+at
so time=4s
v=4m/s
u=12m/s
so a=(4-12)/4
a=-8/4
a=-2m/s^2
-ve tell about the opposite direction.
now force = ma
so F=0.5×-2
F=-1N
in opposite direction
Similar questions