Question

The weight of body is found to reduce by 30%when immersed in water. The specific gravity of the body

Answer 1

Answer:

Specific Gravity = 10/3 = 3.33

Explanation:

The weight of body is found to reduce by 30%when immersed in water. The specific gravity of the body

Let say Weight of Body in Air =  10W

Weight of body when immeresed in Water = 10 W  - (30/100)10W = 7W

Reduction in Weight =  10W - 7W = 3W

Mass in Air = 10W/g

3W = Volume Displaced * Water Density * g

=> Volume Displaced = 3W /(Water Density * g)

Density of body  = Mass in Air/ Volume

=> Density of body = (10W/g)(3W /(Water Density * g))

=> Density of body =  10 * Water Density / 3

=> Density of body / Water Density = 10/3

=> Specific Gravity = 3.33