Question

. The weight of Ca present in Ca(NO3)2, that contains
20g of nitrogen, is :

Answer 1

Explanation:

28g N = one mole molecule of Ca(NO3)2. 20 g N = 1x 20 /28 = 0.71 mole of Ca(NO3)2. One molecule of Ca(NO3)2 contains 2 atoms of N. 0.71 mole Ca(NO3)2 = 40 x 0.71 = 28.4 g Ca.

Answer 2

Answer:

28.4g of Ca

Explanation:

20g N = 1×20/28=

0.71 mole of Ca(No3)2

one mole of Ca(No3)

40×0.71=

28.4g of Ca

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