The weight of calcium (in gm) present in 2 litres of 0.2M
calcium sulphate solution is (at.wt.of Ca=39.75)
1) 10 2) 15 3) 13.6 4) 15.9
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Answer:
molarity = given mass/molar mass x volume of solution in litres..
0.2=a/39.75 x 2
a = 0.4 x 39.75 = 15.9
so d option is correct...
Explanation:
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