Question

the weight of CO2 formed when 25g of CaCO3 on heating
​

Answer 1

answer

Chemical reaction involved is:

CaCO

3

→CaO+CO

2

Molar mass of CaCO

3

=40+12+16×3=100 g

According to the balanced reaction 100 g of CaCO

3

produces 1 mol of CO

2

i.e. 22.4 L at STP.

∴50 g CaCO

3

will produce

100

22.4

×50=11.2 L CO

2

at STP.

Answer 2

Answer:

11 g

Explanation:

25g is 0.25 moles.

CaCO3---> CaO+CO2

Mole ratio of CaCO3 to CO2 is 1:1. So 0.25 moles of CaCO3 gives 0.25 moles of CO2.

Hence 0.25 moles of CO2 is 44/4 g=11 g.

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