Question

the weight of CU deposited from cuso4 silutiom by the passage of 50 coulomb of electricity is​

Answer 1

Answer:

Electro Chemistry

Explanation:

★ Given ;

Cu atoms in Cuso4 solution

Charge passes ( Q ) = 50 C

Weight ( W ) = ??

we know that ;

★ Weight / Equivalent mass = Charge / Farad

» Equivalent mass ( E ) of Cuso 4 = 2

» Charge = 50 C

» 1 Farad ( F ) = 96500 C

Now ;

W / E = Q / F

W / 2 = 50 / 96500

W = 100 / 96500

W = 1 / 965

W = 0.001 gm of Copper is deposited

Answer :- weight of copper deposited is 0.001 gm

Answer 2

At cathode,

Cu 2+2e- --->Cu2+

therefire no of electrons exchanged =2

hence nfactor is 2

$\frac{wt \times n \: factor}{mol.wt} = \frac{charge}{96500} \\ wt = \frac{ 50 \times 63.5 }{96500 \times 2} \\ wt = 0.016g$

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