The weight of H2C2O42H20 required to prepare 500 ml of 0.2ND solution is
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The hydrated form of oxalic acid is represented by C2H2O4.2H2O
It is a dibasic acid with a valency factor of 2.
Normality = Molarity/2
hence, 0.5 N = 0.5/2 M
Volume = 500 ml = 0.5 L
Moles = Molarity X Volume
= 0.5 x 0.5 /2
= 0.125 moles
Molecular weight of oxalic acid is 126 g/mol
Therefore, mass of oxalic acid needed to prepare 500 mL of 0.2N solution = 0.125 x 126 g/mol
= 15.75 g
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