Question

)
The weight of hydrogen deposited at cathode
when 965 amperes current is passed for
100 seconds through acidulated water is
1) 0.1g 2) 0.01g 3) 1g 4) 2g​

Answer 1

Answer:

100 sec ke jagah 112 sec hoga...ans 1g

Explanation:

Reduction at cathode: 2H+(aq)+2e−→H2(g)

At N.T.P, 22.4 L (or 22400 mL) of  H2= 1 mole of  H2

112 mL of  H2=22400112×1=0.005  mole of  H2

Moles of H2 produced =96500(C/mole−)I(A)×t(s)× mole ratio

0.005mol=96500(C/mole−)I(A)×965s× 2 mol e− 1 mol H2  

I=1A

Answer 2

Answer:

1 gram is ur answer option (3)

Explanation:

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