The weight of lifter lift a load of 200 kgf to a height of 2m in a 5s calculate the work done and power developed by him
Answers
Answered by
6
Answer:
1000 watt
Explanation:
Force =mass ×gravity
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F=200×10
=200N
Work done =d×f
2.5×2000=5000joule
The power developed by him
Power=w÷time taken
P=5000÷5=1000watt
Answered by
37
Answer:
5000 J
1000 W
Explanation:
Force = 200 Kgf
[ 1 Kg = 10 N ]
Force = 200 × 10
Force = 2000 N
Time = 5 sec
Height = 2.5 m
Work done = mgh [Force × Height]
Work = 2000 × 2.5
Work = 5000 J
Power = Energy/Time
Power = 5000/5
Power = 1000 W
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