The weight of Manesh is 3 kg less than twice the weight of Bhavesh. If
their total weight is 78 kg, find the weight of both.
Answers
Answered by
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Step-by-step explanation:
- let weight of manesh be x
- let weight of Bhavesh be y
- x+y=78 eq . 1 ( given )
- x=2y-3 eq. 2 ( from the given data)
- from 1 & 2
- 2y-3+y=78
- 3y=75
- y=25
- put y value in 2
- we get
- x=47
- hence weight of manesh is 47 kg and weight of Bhavesh is 25 kg ...
Answered by
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Answer:
Thus Wt of Bhavesh=27 kg
and wt of Manesh=2*27-3
=54-3=51 kg
Step-by-step explanation:
LET WT OF BHAVESH IS =x
THEN WT OF MANESH IS=2x-3
sum of wt x+2x-3=78
3x=81
x=81/3=27
Thus Wt of Bhavesh=27 kg
and wt of Manesh=2*27-3
=54-3=51 kg
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