Math, asked by sy959657, 7 months ago

The weight of Manesh is 3 kg less than twice the weight of Bhavesh. If
their total weight is 78 kg, find the weight of both.​

Answers

Answered by 06039
0

Step-by-step explanation:

  • let weight of manesh be x
  • let weight of Bhavesh be y
  • x+y=78 eq . 1 ( given )
  • x=2y-3 eq. 2 ( from the given data)
  • from 1 & 2
  • 2y-3+y=78
  • 3y=75
  • y=25
  • put y value in 2
  • we get
  • x=47
  • hence weight of manesh is 47 kg and weight of Bhavesh is 25 kg ...
Answered by Anonymous
0

Answer:

Thus Wt of Bhavesh=27 kg

and wt of Manesh=2*27-3

=54-3=51 kg

Step-by-step explanation:

LET WT OF BHAVESH IS =x

THEN WT OF MANESH IS=2x-3

sum of wt x+2x-3=78

3x=81

x=81/3=27

Thus Wt of Bhavesh=27 kg

and wt of Manesh=2*27-3

=54-3=51 kg

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