Chemistry, asked by gagan2526, 11 months ago

The weight of MgCo3, required for the preparation of 12g of MgSO4 is​

Answers

Answered by sulo53
20

Answer:

8.4g

Explanation:

MgCO3 + H2SO4 - MgSO4 +CO2+H2O

molecular weight of MgCO3 is 84g

84g of MgCO3 produces 120g of MgSO4

? produces 12g of MgSO4

  • 12×84/120 =8.4g
Answered by dheeraj170908
3

Answer:

8.4g

explanation

MgCO3 + H2SO4 - MgSO4 +CO2+H2O

molecular weight of MgCO3 is 84g

84g of MgCO3 produces 120g of MgSO4

? produces 12g of MgSO4

12×84/120 =8.4g

Previous Question
Next Question
Similar questions
Math, 5 months ago
what is exact definition of fraction? ​
Science, 5 months ago
Q.write the name of state of mater?​
Hindi, 5 months ago
३) चूक कीबरोबरते लिहा. विजेवर चालणारी गाडी ही विग्रेजांची विलायती भुताटकी होती.​
Science, 11 months ago
Match the agricultural implements given in column A with their use given in column B. 1 2 3 4 Column A Sickle Hoe Seed Drill Sprinkler A B C D Column B Ploughing Sowing Harvesting Irrigation​...
Science, 11 months ago
difference Between periodic and non periodic motion ​...
Social Sciences, 1 year ago
Why are defective and low quality goods available in the market?
Math, 1 year ago
answer 7th question please...
Social Sciences, 1 year ago
what is the population of India according to 2001 and 2011 census...