Math, asked by faidkhan1012, 2 months ago

the weight of Mohit and Yogesh are in the ratio 4:3. If Mohit's weight increases by 2kg and Yogesh's weight decreases by 3 kg, the ratio of their weights becomes 31:21. Find their original weights.
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Answers

Answered by asahilthakur
5

Answer:

Let the ratio be 4x:3x.

According to Question,

(4x+2) / (3x-3) = 31/21

=> 21 (4x+2) = 31 (3x-3)

=> 84x + 42 = 93x - 93

=> 42+93 = 93x-84x

=> 135 = 9x

=> x = 135/9

=> x = 15 kg

Weight of Mohit = 4×15 kg = 60 kg

Weight of Yogesh = 3×15 kg = 45 kg

Answered by Anonymous
22

Answer :-

  • Weight of Mohit = 60Kg

  • Weight of Yogesh = 45Kg

Given :-

  • The weight of Mohit and Yogesh are in the ratio 4:3.

  • If Mohit's weight increases by 2kg and Yogesh's weight decreases by 3 kg, the ratio of their weights becomes 31:21

To Find :-

  • Their original weight.

Step By Step Explanation :-

We know that the weight of Mohit and Yogesh are in the ratio 4:3. If Mohit's weight increases by 2kg and Yogesh's weight decreases by 3 kg, the ratio of their weights becomes 31:21 .

Let us consider the present weight of Mohit and Yogesh be 4x and 3x.

Now equation will be ⤵

  \bigstar \boxed{ \sf{ \pink{\cfrac{4x + 2}{3x - 3}  =  \cfrac{31}{21} }}}

Now let us find the value of x !!

  \implies\sf \: \cfrac{4x + 2}{3x - 3}  =  \cfrac{31}{21}  \\  \\ \implies\sf21(4x + 2) = 31(3x - 3) \\  \\\implies\sf 84x+ 42 = 93x - 93 \\  \\\implies\sf 42 + 93 = 93x - 84x \\  \\\implies\sf 135 = 9x \\  \\ \implies\sf  \cancel\cfrac{135}{9}  = x \\  \\ \implies\sf15 = x

x = 15

Therefore weight of Mohit => 4 × 15 => 60Kg and weight of Yogesh => 3 × 15 => 45Kg

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