Chemistry, asked by madhureddy660, 11 months ago

the weight of NaCl present in 250 ml of 0.1 N solution is

Answers

Answered by udayasankarakula

5

Answer:

1.4625

Explanation:

N=weight of Nacl/gram equivalent weight of Nacl*1000/v(ml)

0.1=w/58.5*1000/250

w=0.1*58.5/4

w=1.46

Answered by rajkotiyapragna24

1

Explanation:

2.45 answer was be come

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