Chemistry, asked by valydrinkard, 10 months ago

The weight of naphthalene in your sample could be determined either by difference (as in this experiment) or by directly weighing the amount of solid collected on the evaporating dish. Which method is a more accurate method?

Answers

Answered by poojacrbs

1

Answer:

sorry but i have not studied these topics yet . very sorty

Answered by monisha11ravi

0

Answer:

Weight of the naphthalene is different

Explanation:

(in which experiment)

Previous Question

Next Question

Similar questions

Math, 5 months ago

4. If the base of isosceles triangle is 4 cm and the perimeter of triangle is 10 cm then find the length of two equal sides.

Hindi, 5 months ago

1) Reason for MP3 is a popular format for music file sharing is:- a) MP3 file work equally well for text, graphics & music. b) MP3 compression is lossless. c) MP3 compression is reduces file sizes considerably with minimal loss of music quality. d) MP3 file contain DRM technology. subject- web application...

Math, 5 months ago

Draw symmetry of 8, 0 and 3...

Math, 10 months ago

Why does Anne give a brief sketch about her family in the diary? * She liked talking about her family To introduce Kitty to her family Because no one would understand and bileve in Kitty without it introduction of family members is mandatory...

Math, 10 months ago

If log(x - y)- log 5 - 1/2 log x - 1/2 log y=0, then x/y+y/x = ...

Social Sciences, 1 year ago

What are the newly created jobs for young people in your area? ( Refer the paragraph under the heading ‘New Skills and New Jobs’)...

Chemistry, 1 year ago

The criterion of spontaneity in terms of Gibbs energy is the same as that laid down by second law of thermodynamics. How?

Physics, 1 year ago

A radio can tune over the frequency range of a portion of MW broadcast band: (800 kHz to 1200 kHz). If its LC circuit has an effective inductance of 200 μH, what must be the range of its variable capacitor? [Hint For tuning, the natural frequency i.e., the frequency of free oscillations of the LC circuit should be equal to the frequency of the radiowave.]...