Chemistry, asked by tishagandhi16, 11 months ago

The weight of nitric oxide (NO) having same number of oxygen atoms are present in 92 g of nitrogen dioxide, is how much

Answers

Answered by BrainlyRonaldo
4

Nitric oxide

Chemical formula ⇒ NO

Molar mass ⇒ 30.006 g·mol−1

for 92 g 2760.552

Answered by qwsuccess
6

The weight of nitric oxide containing the same number of oxygen atoms as present in 92g of nitrogen dioxide is equal to 120 g.

  • Molar mass of nitrogen dioxide(NO2) is equal to 46g/mole.
  • Molar mass of nitric oxide(NO) is equal to 30g/mole.
  • 92 g of nitrogen dioxide means 2 moles of nitrogen dioxide.
  • Since each atom of nitrogen dioxide contains 2 atoms of oxygen, 2 moles of nitrogen dioxide will contain 4 moles of oxygen.
  • 4 moles of oxygen will be present in 4 moles of nitric oxide.
  • Hence, weight of 4 moles of nitric oxide is equal to 120g.
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