Chemistry, asked by bidhanch, 6 months ago

The weight of one litre of a gas at 27 degree Celsius and 600mmHg pressure is 0.8 gram. What is its vapour density and molecular weight ?​

Answers

Answered by Anonymous
6

Weight of 1L of a gas =0.8 g(Given)

Therefore,

PV = nRT

n = PV/RT

n = 0.789 atm. × 1 L / 0.0821×300 K

Therefore,

n = 288.62 mol.

molecular weight = 0.8/288.62 = 0.0027

∴ Vapour density = Molar mass/2

= 0.0027/2

= 0.00135.

Answered by Anonymous
1

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