The weight of one litre of a gas at 27 degree Celsius and 600mmHg pressure is 0.8 gram. What is its vapour density and molecular weight ?
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Weight of 1L of a gas =0.8 g(Given)
Therefore,
PV = nRT
n = PV/RT
n = 0.789 atm. × 1 L / 0.0821×300 K
Therefore,
n = 288.62 mol.
molecular weight = 0.8/288.62 = 0.0027
∴ Vapour density = Molar mass/2
= 0.0027/2
= 0.00135.
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