Question

The weight of oxygen required to to form 40 grams of S*O_{3} by burning required amount of Sulphur:

please answer fast​

Answer 1

Answer:

Atomic weight of Sulphur is 32 grams. Atomic weight of Oxygen is 16 grams.

Molecular weight of SO

2

is 64 grams.

32 grams of Oxygen reacts with 32 grams of Sulphur to produce SO

2

1 gram of Oxygen will react with

32

32

gram of Sulphur

Thus 16 grams of Oxygen will react with 16 grams of Sulphur to produce SO

2

Now, this 16 grams of Sulphur will be converted to one mole of Sulphur Trioxide.

32 grams of Sulphur requires 48 grams of Oxygen to produce SO

3

1 gram of Sulphur requires

32

48

grams of Oxygen

Thus, 16 grams of Sulphur will require 24 Grams of Oxygen (by unitery method)