The weight of oxygen required to to form 40 grams of S*O_{3} by burning required amount of Sulphur:
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Atomic weight of Sulphur is 32 grams. Atomic weight of Oxygen is 16 grams.
Molecular weight of SO
2
is 64 grams.
32 grams of Oxygen reacts with 32 grams of Sulphur to produce SO
2
1 gram of Oxygen will react with
32
32
gram of Sulphur
Thus 16 grams of Oxygen will react with 16 grams of Sulphur to produce SO
2
Now, this 16 grams of Sulphur will be converted to one mole of Sulphur Trioxide.
32 grams of Sulphur requires 48 grams of Oxygen to produce SO
3
1 gram of Sulphur requires
32
48
grams of Oxygen
Thus, 16 grams of Sulphur will require 24 Grams of Oxygen (by unitery method)
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