Question

the weight of rahul is 5 kg more than sacn the weight of samir is 12 kg less than double the weight of sacn if the total weight of all the three is 93 find the weight of each one of them

Answer 1

Let weight of sacn be x. Then weight of Rahul=x+5. weight of Samir=2x-12. Total weight=93 (x+5)+x+(2x-12)=93. 4x-7=93. 4x=93+7. 4x=100. x=100/4=25. weight of Rahul=25+5=30kg. weight of sacn=x=25kg and weight of Samir=2x-12=2(25)-12=38kg

Answer 2

let the weight of sacn be "x"
weight of rahul is 5kg more than sacn
  = (x + 5)kg
weight of samir is 12kg less than the double the weight of sacn
  = (2x - 12)kg
total weight of 3 persons = 93
so,
    = x + (x +5) + (2x - 12) = 93
    = 4x - 7 = 93
    = 4x = 93 + 7
    = 4x = 100
    = x = 100/4
    = x = 25
therefore,
         weight of sacn = x = 25kg
         weight of rahul = x + 5 = 25 + 5 = 30kg
         weight of samir = 2x - 12 = 2 x 25 - 12 = 50 - 12 = 38kg