Question

The weight of the fruit is controlled by 3 pairs of polygenes if the base weight of the fruit 18 gm and the max weight is 54 gm then what will be the weight of the fruit having the genotype AABBcc and AaBbcc

Answer 1

Answer:

42 and 30 gm respectively

Explanation:

each recessive gene(r) contributes 3gm as aabbcc =6r=18  /r=3

each dominant gene(R) contributes 9gm as AABBCC=6R=54 /R=9

AABBcc=4*9+2*3=36+6=42

AaBbcc=2*9+4*3=18+12=30.

Answer 2

Answer:

The weight of the fruit having the genotype

AABBcc = 42 gm

AaBbcc = 30 gm

Explanation:

Let r be the Recessive gene of the fruit with three pair of polygene

:- aabbcc= 18 gm

r+r+r+r+r+r= 18

6r = 18

r=3 gm

Let R be the Dominant gene of the fruit

:- AABBCC= 54gm

6 R = 54

R = 9 gm

Then

AABBcc = 2R+2R+2r

=2(9)+2(9)+2(3)

= 18+18+6

=42

AaBbcc = R+r+R+r+r+r

=2R+4r

= 2(9)+4(3)

=18+12

= 30