Question

The weight of the iron which will be converted into its oxide fe3o4 by the action of 14.4g steam on it is​

Answer 1

Answer Expert Verified
= 0.6 moles of iron will react with 0.8 moles of steam.

Answer 2

Answer:

33.6 grams of iron is converted into Fe3O4.

Explanation:

Chemical equation is :-

 $3Fe+4H_{2}O------ - > Fe_{3}O_{4} +4H_{2}$

Here, 4 moles of steam needs 3 moles of iron.

i.e.,  4*18 = 72g of steam needs 3*56 = 168 g of iron.

So, 14.4 g of steam requires x g of iron.

Therefore,   $\frac{72}{14.4}= \frac{168}{x}$

               => x = 33.6 grams.