the weight of the table is four times the weight of a chair. Then the linear equation corresponding to this is
x-4y=0 (b) x+4y=0 (c) y-4x=0 (d) y+4x=0
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Step-by-step explanation:
If weight of table is 'x' and of chair is 'y'.
Then (a){x-4y=0} is correct.
&
If weight of table is 'y' and of chair is 'x'.
Then (c){y-4x=0} is correct.
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