Question

the weight of the uniform metre rule is 1.5 n calculate the force exerted by the pivot on the metre rule

Answer 1

Explanation:

The answer in the back of the book say it is magnitude of 0.5N downwards, I have tried every combo of equation from m=f*d to W=m*g There are 3 question before, which I don't think are relevant to this question. Which I answers and got right. I have drawn a diagram to show what the meter rule looks like.