Math, asked by Vickydhakane, 2 months ago

The weight of the word x = 11100 in B5 is​

Answers

Answered by pulakmath007
8

SOLUTION

TO DETERMINE

The weight of the word x = 11100 in   \sf{ {B}^{5} }

CONCEPT TO BE IMPLEMENTED

Weight of a word

If   \sf{x \in {B}^{n} } be a word then the weight of the word x is defined as the number of one's (1 's) in the word. It is denoted by | x |

EVALUATION

Here we have to find the weight of the word x = 11100 in   \sf{ {B}^{5} }

So the word is

 \sf{x = 11100}

In the word x the number of one's ( 1 's ) = 3

Hence the required weight of the word

 \sf{ =  |x| }

 \sf{ = 3}

FINAL ANSWER

The weight of the word x = 11100 in   \sf{ {B}^{5} } = 3

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Answered by yashchirdhani
0

Answer:

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