The weights in grams of 50 oranges picked at random from a consignment are as follows: 131,113,82,75,204,81,84,118,104,110,80,107,111,141, 136,123,90,78,90,115,110,98,106,99,107,84,76,186,82, 100,109,128,115,107,115,119,93,187,139,129,130,68, 195,123,125,111,92,86,70,126 Form the grouped frequency table by dividing the variable range into intervals of equal width, each corresponding to 20gms in such a way that the mid-value of the first class corresponds to 70 gms.
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Answers
Answer:
Step-by-step explanation:
Upper Limit - Lower Limit = Width
It is given Width is 20.
So, Upper Limit - Lower Limit = 20 --- (1)
(Upper Limit + Lower Limit) / 2 = Mid Value
So, (Upper Limit + Lower Limit) / 2 = 70
So, (Upper Limit + Lower Limit) = 140 --- (2)
Solving (1) and (2) , we get
Upper Limit = 80
Lower Limit = 60
Frequency distribution table as below based on the consignment data :-
Class Interval | Frequency
60-80 5
80-100 13
100-120 17
120-140 10
140-160 1
160-180 0
180-200 3
200-220 1
Step-by-step explanation:
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