The weights (in kg) of 45 students of a class are given
in the following distribution table. Determine the
value of weight x which is such that the number of
students having weight less than x kg is same as the
number of students having weight more than x kg.
Answers
Given : The weights (in kg) of 45 students of a class
To find : the value of weight x which is such that the number of students having weight less than x kg is same as the number of students having weight more than x kg.
Solution:
We need to find Median Here:
Below 45 5 5 - 45
Below 50 11 6 45 - 50
Below 55 15 4 50 - 55
Below 60 22 7 55 - 60
Below 65 38 16 60 - 65
Below 70 45 7 65 - 70
Total Students = 45
23 rd student is median Student
Which lies in 22 - 38
Median = 60 + 5 x (45/2 - 22) /16
= 60 + 5 x 0.5/16
= 60 + 0.15625
= 60.16 kg
60.16 kg is the Weight such that number of students having weight less than 60.16 kg is same as the number of students having weight more than 60.16 kg.
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